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4x^2+80x-9600=0
a = 4; b = 80; c = -9600;
Δ = b2-4ac
Δ = 802-4·4·(-9600)
Δ = 160000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{160000}=400$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(80)-400}{2*4}=\frac{-480}{8} =-60 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(80)+400}{2*4}=\frac{320}{8} =40 $
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